Let be a triangle such that , and . Find the area of the triangle.

**Solution**

Since it follows from the law of sines that

Hence . Thus,

To completely justify the title of the post we give another solution based on the following proposition:

**Proposition: **Let be a given triangle such that . Prove that

*Proof: *We are working on the following figure.

Let be the bisector of . Then:

and the result follows.

Now, the area of the initial triangle is given by Heron’s formula.